$$W = \Delta KE$$
where $v = 0$ (final velocity), $u = 4$ m/s (initial velocity), $a = -\frac{5}{2}$ m/s$^2$ (acceleration), and $s$ is the displacement.
where $W$ is the net work done and $\Delta KE$ is the change in kinetic energy. Let's consider some problems and their solutions:
A force of 10 N is applied to an object, causing it to move 5 m in the direction of the force. Calculate the work done.
Now, we can calculate the work done:
| Type: | FREE |
| Server IP: | 167.99.70.250 |
| Location: | Singapore |
| protocol SSH: | ✅ 3001 |
| protocol OSSH: | ✅ 3002 |
| FRONTED-MEEK-OSSH: | ✅ 443 |
| FRONTED-MEEK-HTTP-OSSH: | ✅ 80 |
| Active_Days: | 7 |
| Available: | 197 of 200 |
$$W = \Delta KE$$
where $v = 0$ (final velocity), $u = 4$ m/s (initial velocity), $a = -\frac{5}{2}$ m/s$^2$ (acceleration), and $s$ is the displacement.
where $W$ is the net work done and $\Delta KE$ is the change in kinetic energy. Let's consider some problems and their solutions:
A force of 10 N is applied to an object, causing it to move 5 m in the direction of the force. Calculate the work done.
Now, we can calculate the work done:
| Type: | FREE |
| Server IP: | 65.20.76.242 |
| Location: | other |
| Domain: | 65.20.76.242 |
| protocol SSH: | ✅ 3001 |
| protocol OSSH: | ✅ 3002 |
| FRONTED-MEEK-OSSH: | ✅ 443 |
| FRONTED-MEEK-HTTP-OSSH: | ✅ 80 |
| Active_Days: | 1 |
| Available: | 1 of 2 |